Convert Megaelectronvolts (MeV) to Foot-pounds (ft⋅lb)

Enter a value below to convert Megaelectronvolts (MeV) to Foot-pounds (ft⋅lb).

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Conversion:

1 Megaelectronvolts (MeV) = 1.1817030535e-13 Foot-pounds (ft⋅lb)

How to Convert Megaelectronvolts (MeV) to Foot-pounds (ft⋅lb)

1 mev = 1.1817030535e-13 ftlb

1 ftlb = 8462362833300 mev

Example: convert 15 Megaelectronvolts (MeV) to Foot-pounds (ft⋅lb):

25 mev = 2.9542576338e-12 ftlb

Megaelectronvolts (MeV) to Foot-pounds (ft⋅lb) Conversion Table

Megaelectronvolts (MeV)Foot-pounds (ft⋅lb)
0.01 mev1.1817030534999998e-15 ftlb
0.1 mev1.1817030535000001e-14 ftlb
1 mev1.1817030535e-13 ftlb
2 mev2.363406107e-13 ftlb
3 mev3.5451091605e-13 ftlb
5 mev5.9085152675e-13 ftlb
10 mev1.1817030535e-12 ftlb
20 mev2.363406107e-12 ftlb
50 mev5.9085152675e-12 ftlb
100 mev1.1817030535e-11 ftlb
1000 mev1.1817030535e-10 ftlb

Megaelectronvolts (MeV)

Definition

A megaelectronvolt (MeV) is a unit of energy equal to 1,000,000 electronvolts, or approximately 1.602 × 10⁻¹³ joules.

History

The MeV became essential with the development of nuclear physics and particle accelerators in the mid-20th century, particularly for describing nuclear binding energies and particle collision energies.

Current use

MeV are the standard unit for nuclear reaction energies, gamma-ray spectroscopy, radiation therapy dosimetry, and high-energy particle physics experiments.

Foot-pounds (ft⋅lb)

Definition

A foot-pound (ft⋅lb) is an imperial unit of energy equal to the work done when a force of one pound-force moves an object one foot. It equals approximately 1.35582 joules.

History

The foot-pound has been used in English-speaking countries since the early days of mechanical engineering. It was the standard unit for torque and mechanical work before the joule gained prominence.

Current use

Foot-pounds are widely used in the US for measuring torque in automotive and mechanical applications, firearm muzzle energy, and mechanical work in engineering specifications.